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(18x^2+23x-96)/(3x^2+35x-12)=1
We move all terms to the left:
(18x^2+23x-96)/(3x^2+35x-12)-(1)=0
Domain of the equation: (3x^2+35x-12)!=0We multiply all the terms by the denominator
We move all terms containing x to the left, all other terms to the right
3x^2+35x!=12
x∈R
(18x^2+23x-96)-1*(3x^2+35x-12)=0
We get rid of parentheses
18x^2+23x-1*(3x^2+35x-12)-96=0
We move all terms containing x to the left, all other terms to the right
18x^2+23x-1*(3x^2+35x-12)=96
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